One should examine which of the unknown solutions AE, which contains ions, the pH value they have, what containing chloride ions and which contains sulphate ions.
The lab involves using dip electrodes to find out if there are ions, BTB find out the pH of the solutions are, using silver nitrate (AgNO3) to see if there are chloride ions (Cl) in the solutions and by means of barium chloride (BaCl2) to find out if there are sulphate ions (SO42-) in the solutions.
Solution A: Is not an ionic solution, is neutral, does not contain chloride ion, but containing sulfate ions.
Solution B: Is an ionic solution, is neutral, chloride ions and not sulfate ions.
Solution C: Is an ionic solution is acidic, does not contain chloride ion, but containing sulfate ions.
Solution D: Is an ionic solution is alkaline, examined not whether there was chloride ions or sulfate ions due to the removal of the solution after the pH test.
Solution E: Is an ionic solution is acidic, chloride ions and not sulfate ions.
The conclusion is that solution A is a molecular compound in the solution is neutral and one of the substances is Sulphur (S).
B ions in the solution which is neutral, and one of the topics is Chlorine (C).
C is the ions in the solution is acidic and one of the topics is Sulphur (S).
D is as ions in solution is basic.
E is the ions in the solution is acidic and one of the topics is Chlorine (C).
Materials and methods:
1 tube rack
7 pipettes (one for each cup)
5 cups with unknown solutions
2 cups (one with silver nitrate AgNO3 and one with Barium chloride BaCl2)
1 dip electrode
1. To determine if the solution contains ions, then use a dip electrodes. Because the ions conduct electricity and doppelektroden reads about a solution conducts electricity. You put down doppelektroden in the unknown solutions and press a button on the device, if the lights are on, you know that the solution conducts electricity.
2. Since then one of a bit of the unknown solutions to the test tubes with the help of the pipettors. This time you should find out if the solutions are acidic, neutral or basic, in order to determine the need to use the BTB. It drops down a bit BTB in test tubes and see what color the solution becomes. Removing the one that turns blue, then alkaline.
3. Sen examines whether the solution containing chloride ions Cl. Silver nitrate AgNO3 is the reagent of chloride ions Cl. The new test tube of the same unknown solutions, mixes it in silver nitrate AgNO3. If the solution in the test tube containing chloride ions so the solution will be cloudy. Sorting then remove the tube containing chloride ions.
4. In the remaining test tubes shall examine the solutions containing sulfate ions SO42-. Barium chloride BaCl2, the reagent of sulfate ions SO42-. Adding Barium chloride BaCl2 in test tubes and the solutions in test tubes containing sulphate ions, the solutions will become cloudy.
Beyond Solutions ionic solutions pH chloride ions, sulfate ions
A Yes Neutral No Yes
B Yes Neutral Yes ----
C Acid Yes No Yes
D Yes alkalines ---- ----
E Yes Yes Acid ----
Conclusions and discussion:
1. If the lights loose on doppelektroden it was an ionic solution = conducts current.
2. If the solution is colored by BTB in any of these colors, yellow, green or blue, it was either acidic, neutral or basic. Yellow = Acid, Green = Neutral, Blue = alkalines.
3. If the solution containing chloride ions (Cl-) when dripped Silver nitrate (AgNO3), forming a sparingly soluble salt (cloudy), silver chloride (AgCl).
4. If the remaining solutions containing sulfate ions (SO42-) while adding Barium chloride (BaCl2), forming a sparingly soluble salt (cloudy), barium sulfate (BaSO4).based on 4 ratings Determine topic using simple methods,