Schoolwork

Abstract:

You should examine which of the unknown solutions AE, which contains ions, which pH value they have, those that contain chloride ions and which contains sulfate ions.
Laboration is that by using the dip electrode to determine if there are ions, with the BTB find out the pH of the solutions are, using silver nitrate (AgNO3) to see if there are chloride ions (Cl-) in solutions and with the help of barium (BaCl2) to find out if there are sulfate ions (SO42-) in solutions.
Solution A: Is not a jonlösning, is neutral, does not contain chloride ions, but containing sulfate ions.
Solution B: Is a jonlösning, is neutral, chloride ions and sulfate ions do not.
Solution C: Is a jonlösning, is acidic, does not contain chloride ions, but containing sulfate ions.
Solution D: Is a jonlösning, is alkaline, it was examined if there were no chloride ions or sulfate ions due to the removal of the solution after the pH test.
Solution E: Is a jonlösning, is acidic, chloride ions and sulfate ions do not.
The conclusion is that solution A is a molecular compound in solution which is neutral and one of the substances are sulfur (S).
B ions in the solution which is neutral and one of the topics are Chlorine (C).
C is ions in the solution is acidic and one of the substances are sulfur (S).
D is the ions in the solution is alkaline.
E is the ions in the solution is acidic and one of the topics are Chlorine (C).

Materials and methods:

9 test tubes
1 test tube rack
7 pipettes (one for each cup)
5 cups with unknown solutions
2 cups (one with Silver Nitrate AgNO3 and one with Barium chloride BaCl2)
1 dip electrode
BTB

1. To find out if the solution contains ions, so you could apply a dip electrode. Because the ions conduct electricity and doppelektroden reads about a solution conducts electricity. Putting down doppelektroden in the unknown solutions, and press a button on the device, the lights do you know that the solution to conduct electricity.

2nd Then as the one over a bit of the unknown solutions into test tubes using pipettes. This time you should find out if the solutions are acidic, neutral or alkaline, in order to determine it is necessary to use BTB.It drops down a bit BTB in test tubes and see what color the solution becomes. You take away that which turns blue, that is alkaline.

3rd Then examined to determine whether the solution containing chloride ions, Cl. Silver nitrate AgNO3 reagent is the chloride ion Cl-. The new test tube with the unknown solution, is mixed in Silver Nitrate AgNO3. If the solution in the test tube containing chloride ions, then the solution to become cloudy. It then sorts out the tubes containing chloride ions.

4th In the remaining test tubes should be examined whether the solutions containing sulfate ions, SO42-. BaCl2 reagent is barium sulfate ions in SO42-. It appoints Barium chloride BaCl2 in test tubes and on practices in test tubes containing sulfate ions, the solutions become cloudy.

Results:

Unknown Solutions jonlösningar pH of chloride ions, sulfate ions
A neutral No No Yes
B Yes Yes Neutral ----
C Acid Yes No Yes
D Yes Basic ---- ----
E Yes Yes Acid ----

Conclusions and discussion:

1.If the lights on the loose doppelektroden so it was a jonlösning = conduct electricity.

2nd If the color of the solution of BTB in any of these colors, yellow, green or blue, it was either acidic, neutral or alkaline. Yellow = Acid, Green = Neutral, Blue = Basic.

3rd If the solution contained chloride ions (Cl-) when it dripped down Silver nitrate (AgNO3), forms a sparingly soluble salt (cloudy), Silver Chloride (AgCl).

4th If the remaining solutions containing sulfate ions (SO42-) when appointed Barium chloride (BaCl2), forms a sparingly soluble salt (cloudy), Barium sulphate (BaSO4).